ASVAB Math Knowledge Practice Test 546699

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4b - b = -8b + 2y + 1 for b in terms of y.

\(\frac{7}{8}\)y - \(\frac{3}{8}\)
5y - 2
\(\frac{1}{4}\)y - \(\frac{1}{2}\)
\(\frac{1}{4}\)y + \(\frac{1}{12}\)