ASVAB Math Knowledge Practice Test 548482

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 7c + 3c = -6c - 2y + 1 for c in terms of y.

-\(\frac{2}{9}\)y - \(\frac{5}{9}\)
2\(\frac{2}{7}\)y - \(\frac{4}{7}\)
-\(\frac{5}{13}\)y + \(\frac{1}{13}\)
\(\frac{5}{7}\)y - 1\(\frac{2}{7}\)