When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 5c = -6c + 4z + 8 for c in terms of z.
| \(\frac{3}{4}\)z + \(\frac{5}{12}\) | |
| \(\frac{7}{11}\)z + \(\frac{9}{11}\) | |
| -\(\frac{1}{14}\)z + \(\frac{4}{7}\) | |
| -5z - 2\(\frac{1}{3}\) |