ASVAB Math Knowledge Practice Test 548629

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -4a - 5a = 3a - 3z + 1 for a in terms of z.

\(\frac{3}{11}\)z + \(\frac{3}{11}\)
\(\frac{2}{13}\)z + \(\frac{3}{13}\)
1\(\frac{2}{7}\)z - 1\(\frac{2}{7}\)
-\(\frac{2}{7}\)z - \(\frac{1}{7}\)