When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 2c = 3c + 2z - 5 for c in terms of z.
| -2z - 1\(\frac{1}{8}\) | |
| z - 1 | |
| -\(\frac{3}{5}\)z - \(\frac{4}{5}\) | |
| -2\(\frac{2}{3}\)z + 2 |