ASVAB Math Knowledge Practice Test 549758 Results

Your Results Global Average
Questions 5 5
Correct 0 2.93
Score 0% 59%

Review

1

The dimensions of this trapezoid are a = 6, b = 6, c = 7, d = 3, and h = 4. What is the area?

51% Answer Correctly
35
18
32\(\frac{1}{2}\)
15

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(6 + 3)(4)
a = ½(9)(4)
a = ½(36) = \( \frac{36}{2} \)
a = 18


2

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

61% Answer Correctly

obtuse, acute

supplementary, vertical

vertical, supplementary

acute, obtuse


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


3

If side x = 8cm, side y = 14cm, and side z = 12cm what is the perimeter of this triangle?

85% Answer Correctly
28cm
20cm
34cm
26cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 8cm + 14cm + 12cm = 34cm


4

The dimensions of this cylinder are height (h) = 9 and radius (r) = 9. What is the volume?

62% Answer Correctly
392π
49π
25π
729π

Solution

The volume of a cylinder is πr2h:

v = πr2h
v = π(92 x 9)
v = 729π


5

Solve 9c - 2c = -4c + 5z - 9 for c in terms of z.

34% Answer Correctly
-2\(\frac{2}{5}\)z + 1\(\frac{1}{5}\)
\(\frac{7}{13}\)z - \(\frac{9}{13}\)
-1\(\frac{1}{2}\)z - 3\(\frac{1}{2}\)
\(\frac{1}{13}\)z + \(\frac{1}{13}\)

Solution

To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.

9c - 2z = -4c + 5z - 9
9c = -4c + 5z - 9 + 2z
9c + 4c = 5z - 9 + 2z
13c = 7z - 9
c = \( \frac{7z - 9}{13} \)
c = \( \frac{7z}{13} \) + \( \frac{-9}{13} \)
c = \(\frac{7}{13}\)z - \(\frac{9}{13}\)