ASVAB Math Knowledge Practice Test 549758

Question 5 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6a - 5a = 2a + 7x + 6 for a in terms of x.

3x + 1\(\frac{1}{2}\)
-\(\frac{3}{5}\)x + \(\frac{1}{5}\)
1\(\frac{3}{7}\)x + \(\frac{3}{7}\)
\(\frac{1}{5}\)x - 1