When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + 4c = 7c - 2z + 7 for c in terms of z.
| -2\(\frac{1}{6}\)z - 1 | |
| 1\(\frac{7}{8}\)z - \(\frac{5}{8}\) | |
| 6z - 7 | |
| \(\frac{2}{3}\)z - 1\(\frac{1}{2}\) |