| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.96 |
| Score | 0% | 59% |
For this diagram, the Pythagorean theorem states that b2 = ?
c - a |
|
c2 + a2 |
|
c2 - a2 |
|
a2 - c2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
If BD = 23 and AD = 26, AB = ?
| 10 | |
| 15 | |
| 3 | |
| 16 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDA cylinder with a radius (r) and a height (h) has a surface area of:
4π r2 |
|
π r2h |
|
π r2h2 |
|
2(π r2) + 2π rh |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
Simplify (7a)(2ab) + (2a2)(9b).
| 32a2b | |
| 99ab2 | |
| 99a2b | |
| 32ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(7a)(2ab) + (2a2)(9b)
(7 x 2)(a x a x b) + (2 x 9)(a2 x b)
(14)(a1+1 x b) + (18)(a2b)
14a2b + 18a2b
32a2b
If angle a = 52° and angle b = 41° what is the length of angle d?
| 150° | |
| 157° | |
| 128° | |
| 122° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 52° - 41° = 87°
So, d° = 41° + 87° = 128°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 52° = 128°