ASVAB Math Knowledge Practice Test 551400 Results

Your Results Global Average
Questions 5 5
Correct 0 2.44
Score 0% 49%

Review

1

The dimensions of this cube are height (h) = 2, length (l) = 3, and width (w) = 2. What is the surface area?

51% Answer Correctly
32
320
158
150

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 3 x 2) + (2 x 2 x 2) + (2 x 3 x 2)
sa = (12) + (8) + (12)
sa = 32


2

On this circle, line segment CD is the:

46% Answer Correctly

diameter

radius

circumference

chord


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


3

Simplify (8a)(6ab) + (6a2)(7b).

65% Answer Correctly
90ab2
90a2b
182a2b
182ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(8a)(6ab) + (6a2)(7b)
(8 x 6)(a x a x b) + (6 x 7)(a2 x b)
(48)(a1+1 x b) + (42)(a2b)
48a2b + 42a2b
90a2b


4

Solve 5a + 2a = -8a + 9x + 5 for a in terms of x.

34% Answer Correctly
\(\frac{7}{13}\)x + \(\frac{5}{13}\)
-\(\frac{11}{12}\)x + \(\frac{1}{6}\)
\(\frac{2}{3}\)x + 3
\(\frac{1}{6}\)x - \(\frac{1}{4}\)

Solution

To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.

5a + 2x = -8a + 9x + 5
5a = -8a + 9x + 5 - 2x
5a + 8a = 9x + 5 - 2x
13a = 7x + 5
a = \( \frac{7x + 5}{13} \)
a = \( \frac{7x}{13} \) + \( \frac{5}{13} \)
a = \(\frac{7}{13}\)x + \(\frac{5}{13}\)


5

The dimensions of this cylinder are height (h) = 3 and radius (r) = 8. What is the surface area?

48% Answer Correctly
12π
32π
176π
80π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(82) + 2π(8 x 3)
sa = 2π(64) + 2π(24)
sa = (2 x 64)π + (2 x 24)π
sa = 128π + 48π
sa = 176π