| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.44 |
| Score | 0% | 49% |
The dimensions of this cube are height (h) = 2, length (l) = 3, and width (w) = 2. What is the surface area?
| 32 | |
| 320 | |
| 158 | |
| 150 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 3 x 2) + (2 x 2 x 2) + (2 x 3 x 2)
sa = (12) + (8) + (12)
sa = 32
On this circle, line segment CD is the:
diameter |
|
radius |
|
circumference |
|
chord |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
Simplify (8a)(6ab) + (6a2)(7b).
| 90ab2 | |
| 90a2b | |
| 182a2b | |
| 182ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(8a)(6ab) + (6a2)(7b)
(8 x 6)(a x a x b) + (6 x 7)(a2 x b)
(48)(a1+1 x b) + (42)(a2b)
48a2b + 42a2b
90a2b
Solve 5a + 2a = -8a + 9x + 5 for a in terms of x.
| \(\frac{7}{13}\)x + \(\frac{5}{13}\) | |
| -\(\frac{11}{12}\)x + \(\frac{1}{6}\) | |
| \(\frac{2}{3}\)x + 3 | |
| \(\frac{1}{6}\)x - \(\frac{1}{4}\) |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
5a + 2x = -8a + 9x + 5
5a = -8a + 9x + 5 - 2x
5a + 8a = 9x + 5 - 2x
13a = 7x + 5
a = \( \frac{7x + 5}{13} \)
a = \( \frac{7x}{13} \) + \( \frac{5}{13} \)
a = \(\frac{7}{13}\)x + \(\frac{5}{13}\)
The dimensions of this cylinder are height (h) = 3 and radius (r) = 8. What is the surface area?
| 12π | |
| 32π | |
| 176π | |
| 80π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(82) + 2π(8 x 3)
sa = 2π(64) + 2π(24)
sa = (2 x 64)π + (2 x 24)π
sa = 128π + 48π
sa = 176π