You need to find the value of b so solve the first equation in terms of z:

-8b + z = -2
z = -2 + 8b

then substitute the result (-2 - -8b) into the second equation:

7b - 9(-2 + 8b) = -9
7b + (-9 x -2) + (-9 x 8b) = -9
7b + 18 - 72b = -9
7b - 72b = -9 - 18
-65b = -27
b = \( \frac{-27}{-65} \)
b = \(\frac{27}{65}\)

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 8 x 2 = \( \frac{16}{2} \) = 8

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

c² - 16c + 64 = 0
(c - 8)(c - 8) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, (c - 8) must equal zero:

If (c - 8) = 0, c must equal 8

So the solution is that c = 8

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

4a - 7a = -3a

A trapezoid is a quadrilateral with one set of parallel sides.