ASVAB Math Knowledge Practice Test 553716

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -3a + 6a = 2a - 5z - 9 for a in terms of z.

z - 1\(\frac{1}{8}\)
4\(\frac{2}{3}\)z - 1\(\frac{2}{3}\)
2\(\frac{1}{5}\)z + 1\(\frac{4}{5}\)
-\(\frac{5}{9}\)z + \(\frac{1}{3}\)