When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4a + 6a = 2a - 5z - 1 for a in terms of z.
| -5\(\frac{1}{2}\)z - \(\frac{1}{2}\) | |
| \(\frac{3}{16}\)z + \(\frac{3}{8}\) | |
| -4z + 2\(\frac{2}{3}\) | |
| \(\frac{1}{6}\)z + \(\frac{2}{3}\) |