| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.91 |
| Score | 0% | 58% |
Which of the following statements about parallel lines with a transversal is not correct?
same-side interior angles are complementary and equal each other |
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all acute angles equal each other |
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all of the angles formed by a transversal are called interior angles |
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angles in the same position on different parallel lines are called corresponding angles |
Parallel lines are lines that share the same slope (steepness) and therefore never intersect. A transversal occurs when a set of parallel lines are crossed by another line. All of the angles formed by a transversal are called interior angles and angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°) and are called corresponding angles. Alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°) and all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other. Same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°).
If BD = 27 and AD = 28, AB = ?
| 2 | |
| 5 | |
| 6 | |
| 1 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDSimplify (3a)(5ab) + (2a2)(7b).
| -a2b | |
| 29a2b | |
| a2b | |
| 72a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(3a)(5ab) + (2a2)(7b)
(3 x 5)(a x a x b) + (2 x 7)(a2 x b)
(15)(a1+1 x b) + (14)(a2b)
15a2b + 14a2b
29a2b
This diagram represents two parallel lines with a transversal. If b° = 162, what is the value of x°?
| 27 | |
| 162 | |
| 161 | |
| 20 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with b° = 162, the value of x° is 162.
The endpoints of this line segment are at (-2, 0) and (2, 2). What is the slope-intercept equation for this line?
| y = x + 1 | |
| y = \(\frac{1}{2}\)x + 1 | |
| y = -1\(\frac{1}{2}\)x + 1 | |
| y = -1\(\frac{1}{2}\)x + 3 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 0) and (2, 2) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(2.0) - (0.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)Plugging these values into the slope-intercept equation:
y = \(\frac{1}{2}\)x + 1