| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.71 |
| Score | 0% | 54% |
For this diagram, the Pythagorean theorem states that b2 = ?
c2 + a2 |
|
c - a |
|
c2 - a2 |
|
a2 - c2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
Which types of triangles will always have at least two sides of equal length?
equilateral and right |
|
equilateral and isosceles |
|
isosceles and right |
|
equilateral, isosceles and right |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.
If the length of AB equals the length of BD, point B __________ this line segment.
bisects |
|
intersects |
|
trisects |
|
midpoints |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.
Which of the following statements about math operations is incorrect?
you can multiply monomials that have different variables and different exponents |
|
you can add monomials that have the same variable and the same exponent |
|
all of these statements are correct |
|
you can subtract monomials that have the same variable and the same exponent |
You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.
Factor y2 - 9y + 20
| (y - 5)(y + 4) | |
| (y + 5)(y + 4) | |
| (y + 5)(y - 4) | |
| (y - 5)(y - 4) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 20 as well and sum (Inside, Outside) to equal -9. For this problem, those two numbers are -5 and -4. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 - 9y + 20
y2 + (-5 - 4)y + (-5 x -4)
(y - 5)(y - 4)