| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.08 |
| Score | 0% | 62% |
A cylinder with a radius (r) and a height (h) has a surface area of:
π r2h2 |
|
2(π r2) + 2π rh |
|
4π r2 |
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π r2h |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
For this diagram, the Pythagorean theorem states that b2 = ?
a2 - c2 |
|
c2 + a2 |
|
c2 - a2 |
|
c - a |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
If a = c = 1, b = d = 5, and the blue angle = 73°, what is the area of this parallelogram?
| 2 | |
| 63 | |
| 5 | |
| 6 |
The area of a parallelogram is equal to its length x width:
a = l x w
a = a x b
a = 1 x 5
a = 5
The formula for the area of a circle is which of the following?
a = π r2 |
|
a = π d2 |
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a = π d |
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a = π r |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
If side a = 2, side b = 7, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{34} \) | |
| \( \sqrt{90} \) | |
| \( \sqrt{58} \) | |
| \( \sqrt{53} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 22 + 72
c2 = 4 + 49
c2 = 53
c = \( \sqrt{53} \)