When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6b + 5b = b - 3y - 1 for b in terms of y.
| 3\(\frac{3}{4}\)y - \(\frac{3}{4}\) | |
| -1\(\frac{1}{3}\)y + 1 | |
| -1\(\frac{3}{5}\)y - \(\frac{1}{5}\) | |
| -4\(\frac{2}{3}\)y - 1\(\frac{1}{3}\) |