| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.24 |
| Score | 0% | 65% |
Solve for b:
-9b - 7 < -5 - 3b
| b < -3\(\frac{1}{2}\) | |
| b < -\(\frac{1}{3}\) | |
| b < \(\frac{1}{7}\) | |
| b < -\(\frac{3}{4}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-9b - 7 < -5 - 3b
-9b < -5 - 3b + 7
-9b + 3b < -5 + 7
-6b < 2
b < \( \frac{2}{-6} \)
b < -\(\frac{1}{3}\)
Which of the following is not a part of PEMDAS, the acronym for math order of operations?
division |
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pairs |
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exponents |
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addition |
When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
If angle a = 25° and angle b = 20° what is the length of angle d?
| 157° | |
| 151° | |
| 160° | |
| 155° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 25° - 20° = 135°
So, d° = 20° + 135° = 155°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 25° = 155°
On this circle, line segment CD is the:
radius |
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circumference |
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chord |
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diameter |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
If AD = 17 and BD = 12, AB = ?
| 3 | |
| 11 | |
| 5 | |
| 10 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BD