ASVAB Math Knowledge Practice Test 558959 Results

Your Results Global Average
Questions 5 5
Correct 0 3.16
Score 0% 63%

Review

1

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

the lengths of all sides are equal

the area is length x width

all interior angles are right angles

the perimeter is the sum of the lengths of all four sides


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


2

The dimensions of this cube are height (h) = 7, length (l) = 6, and width (w) = 2. What is the volume?

83% Answer Correctly
4
32
84
54

Solution

The volume of a cube is height x length x width:

v = h x l x w
v = 7 x 6 x 2
v = 84


3

Which of the following expressions contains exactly two terms?

83% Answer Correctly

monomial

polynomial

quadratic

binomial


Solution

A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.


4

The dimensions of this cylinder are height (h) = 5 and radius (r) = 6. What is the surface area?

48% Answer Correctly
72π
16π
132π
70π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(62) + 2π(6 x 5)
sa = 2π(36) + 2π(30)
sa = (2 x 36)π + (2 x 30)π
sa = 72π + 60π
sa = 132π


5

Solve 3c - 2c = -5c - 7z + 8 for c in terms of z.

35% Answer Correctly
-\(\frac{5}{8}\)z + 1
2\(\frac{3}{7}\)z + \(\frac{1}{7}\)
-13z - 4
-8z + 4\(\frac{1}{2}\)

Solution

To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.

3c - 2z = -5c - 7z + 8
3c = -5c - 7z + 8 + 2z
3c + 5c = -7z + 8 + 2z
8c = -5z + 8
c = \( \frac{-5z + 8}{8} \)
c = \( \frac{-5z}{8} \) + \( \frac{8}{8} \)
c = -\(\frac{5}{8}\)z + 1