When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -9c - 2c = -3c + 9z + 5 for c in terms of z.
| 2\(\frac{2}{5}\)z - 1 | |
| 1\(\frac{2}{7}\)z + \(\frac{2}{7}\) | |
| \(\frac{5}{7}\)z + \(\frac{2}{7}\) | |
| -1\(\frac{5}{6}\)z - \(\frac{5}{6}\) |