| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.83 |
| Score | 0% | 57% |
Factor y2 + 7y - 18
| (y + 2)(y - 9) | |
| (y - 2)(y + 9) | |
| (y + 2)(y + 9) | |
| (y - 2)(y - 9) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -18 as well and sum (Inside, Outside) to equal 7. For this problem, those two numbers are -2 and 9. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 + 7y - 18
y2 + (-2 + 9)y + (-2 x 9)
(y - 2)(y + 9)
If side a = 8, side b = 5, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{89} \) | |
| \( \sqrt{18} \) | |
| 10 | |
| \( \sqrt{17} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 82 + 52
c2 = 64 + 25
c2 = 89
c = \( \sqrt{89} \)
For this diagram, the Pythagorean theorem states that b2 = ?
c2 + a2 |
|
c - a |
|
a2 - c2 |
|
c2 - a2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
The endpoints of this line segment are at (-2, 3) and (2, -7). What is the slope of this line?
| 2 | |
| -2\(\frac{1}{2}\) | |
| 1 | |
| \(\frac{1}{2}\) |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 3) and (2, -7) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-7.0) - (3.0)}{(2) - (-2)} \) = \( \frac{-10}{4} \)This diagram represents two parallel lines with a transversal. If x° = 153, what is the value of c°?
| 10 | |
| 147 | |
| 27 | |
| 26 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with x° = 153, the value of c° is 27.