ASVAB Math Knowledge Practice Test 562195 Results

Your Results Global Average
Questions 5 5
Correct 0 2.78
Score 0% 56%

Review

1

On this circle, line segment CD is the:

46% Answer Correctly

diameter

circumference

radius

chord


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


2

Factor y2 + 11y + 18

54% Answer Correctly
(y - 2)(y + 9)
(y - 2)(y - 9)
(y + 2)(y - 9)
(y + 2)(y + 9)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 18 as well and sum (Inside, Outside) to equal 11. For this problem, those two numbers are 2 and 9. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 + 11y + 18
y2 + (2 + 9)y + (2 x 9)
(y + 2)(y + 9)


3

What is 3a2 + 9a2?

76% Answer Correctly
-6a4
27a4
12
12a2

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

3a2 + 9a2 = 12a2


4

Simplify (8a)(7ab) + (8a2)(8b).

66% Answer Correctly
120a2b
-8ab2
240a2b
8a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(8a)(7ab) + (8a2)(8b)
(8 x 7)(a x a x b) + (8 x 8)(a2 x b)
(56)(a1+1 x b) + (64)(a2b)
56a2b + 64a2b
120a2b


5

Solve -5a + 8a = 6a + 8x + 8 for a in terms of x.

35% Answer Correctly
x - \(\frac{8}{11}\)
-6x - 8
8x + 3
-\(\frac{8}{11}\)x + \(\frac{1}{11}\)

Solution

To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.

-5a + 8x = 6a + 8x + 8
-5a = 6a + 8x + 8 - 8x
-5a - 6a = 8x + 8 - 8x
-11a = + 8
a = \( \frac{ + 8}{-11} \)
a = \( \frac{}{-11} \) + \( \frac{8}{-11} \)
a = x - \(\frac{8}{11}\)