Parallel lines are lines that share the same slope (steepness) and therefore never intersect. A transversal occurs when a set of parallel lines are crossed by another line. All of the angles formed by a transversal are called interior angles and angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°) and are called corresponding angles. Alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°) and all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other. Same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°).

To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

b(b - z)
1(-6)(-6 - 8)
1(-6)(-14)
(-6)(-14)
84

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

z² + 18z + 61 = 2z - 2
z² + 18z + 61 + 2 = 2z
z² + 18z - 2z + 63 = 0
z² + 16z + 63 = 0

Next, factor the quadratic equation:

z² + 16z + 63 = 0
(z + 7)(z + 9) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (z + 7) or (z + 9) must equal zero:

If (z + 7) = 0, z must equal -7
If (z + 9) = 0, z must equal -9

So the solution is that z = -7 or -9

You need to find the value of b so solve the first equation in terms of x:

-3b + x = 3
x = 3 + 3b

then substitute the result (3 - -3b) into the second equation:

-2b - 1(3 + 3b) = -8
-2b + (-1 x 3) + (-1 x 3b) = -8
-2b - 3 - 3b = -8
-2b - 3b = -8 + 3
-5b = -5
b = \( \frac{-5}{-5} \)
b = 1

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

4a⁴ + 9a⁴ = 13a⁴