Your Results | Global Average | |
---|---|---|
Questions | 5 | 5 |
Correct | 0 | 3.16 |
Score | 0% | 63% |
If side a = 4, side b = 6, what is the length of the hypotenuse of this right triangle?
\( \sqrt{40} \) | |
\( \sqrt{52} \) | |
\( \sqrt{2} \) | |
\( \sqrt{34} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 42 + 62
c2 = 16 + 36
c2 = 52
c = \( \sqrt{52} \)
For this diagram, the Pythagorean theorem states that b2 = ?
c2 + a2 |
|
a2 - c2 |
|
c2 - a2 |
|
c - a |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
Find the value of a:
-4a + y = 3
-3a - 9y = -6
-\(\frac{7}{13}\) | |
-\(\frac{16}{37}\) | |
-\(\frac{19}{21}\) | |
-\(\frac{1}{2}\) |
You need to find the value of a so solve the first equation in terms of y:
-4a + y = 3
y = 3 + 4a
then substitute the result (3 - -4a) into the second equation:
-3a - 9(3 + 4a) = -6
-3a + (-9 x 3) + (-9 x 4a) = -6
-3a - 27 - 36a = -6
-3a - 36a = -6 + 27
-39a = 21
a = \( \frac{21}{-39} \)
a = -\(\frac{7}{13}\)
This diagram represents two parallel lines with a transversal. If a° = 18, what is the value of c°?
146 | |
18 | |
13 | |
16 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with a° = 18, the value of c° is 18.
If a = 1, b = 1, c = 7, and d = 2, what is the perimeter of this quadrilateral?
14 | |
11 | |
23 | |
19 |
Perimeter is equal to the sum of the four sides:
p = a + b + c + d
p = 1 + 1 + 7 + 2
p = 11