ASVAB Math Knowledge Practice Test 563295

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3c - 4c = -9c - 3y - 2 for c in terms of y.

\(\frac{1}{2}\)y - 1
\(\frac{1}{12}\)y - \(\frac{1}{6}\)
-\(\frac{9}{10}\)y + \(\frac{9}{10}\)
\(\frac{1}{3}\)y - 1\(\frac{1}{3}\)