When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6a - 8a = -9a + 4x + 1 for a in terms of x.
| \(\frac{4}{5}\)x + \(\frac{1}{15}\) | |
| 3\(\frac{1}{2}\)x + 3 | |
| 5x + 2\(\frac{1}{2}\) | |
| -2\(\frac{3}{4}\)x - 2 |