ASVAB Math Knowledge Practice Test 563879 Results

Your Results Global Average
Questions 5 5
Correct 0 3.13
Score 0% 63%

Review

1

Which of the following is not true about both rectangles and squares?

64% Answer Correctly

the perimeter is the sum of the lengths of all four sides

all interior angles are right angles

the lengths of all sides are equal

the area is length x width


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


2

A(n) __________ is to a parallelogram as a square is to a rectangle.

52% Answer Correctly

triangle

rhombus

quadrilateral

trapezoid


Solution

A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.


3

Simplify (5a)(7ab) - (4a2)(2b).

63% Answer Correctly
43a2b
27a2b
43ab2
72a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(5a)(7ab) - (4a2)(2b)
(5 x 7)(a x a x b) - (4 x 2)(a2 x b)
(35)(a1+1 x b) - (8)(a2b)
35a2b - 8a2b
27a2b


4

Solve for z:
z2 + 7z + 10 = 0

59% Answer Correctly
2 or -5
-2 or -5
9 or 5
-2 or -8

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

z2 + 7z + 10 = 0
(z + 2)(z + 5) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (z + 2) or (z + 5) must equal zero:

If (z + 2) = 0, z must equal -2
If (z + 5) = 0, z must equal -5

So the solution is that z = -2 or -5


5

What is 6a3 + 6a3?

76% Answer Correctly
36a3
a36
6
12a3

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

6a3 + 6a3 = 12a3