| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.00 |
| Score | 0% | 60% |
If BD = 5 and AD = 11, AB = ?
| 17 | |
| 5 | |
| 6 | |
| 20 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDFactor y2 + 7y + 10
| (y + 2)(y + 5) | |
| (y + 2)(y - 5) | |
| (y - 2)(y - 5) | |
| (y - 2)(y + 5) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 10 as well and sum (Inside, Outside) to equal 7. For this problem, those two numbers are 2 and 5. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 + 7y + 10
y2 + (2 + 5)y + (2 x 5)
(y + 2)(y + 5)
What is 4a + 4a?
| 8 | |
| 16a | |
| 8a | |
| a2 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
4a + 4a = 8a
The endpoints of this line segment are at (-2, -4) and (2, 8). What is the slope-intercept equation for this line?
| y = 3x + 2 | |
| y = -3x - 2 | |
| y = -2x + 3 | |
| y = \(\frac{1}{2}\)x + 0 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 2. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -4) and (2, 8) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(8.0) - (-4.0)}{(2) - (-2)} \) = \( \frac{12}{4} \)Plugging these values into the slope-intercept equation:
y = 3x + 2
If the length of AB equals the length of BD, point B __________ this line segment.
trisects |
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bisects |
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midpoints |
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intersects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.