ASVAB Math Knowledge Practice Test 56508

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2c + 3c = c + 9y + 5 for c in terms of y.

1\(\frac{2}{7}\)y + \(\frac{2}{7}\)
6y + 5
\(\frac{7}{9}\)y + \(\frac{1}{3}\)
4y - 6