| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.84 |
| Score | 0% | 57% |
The endpoints of this line segment are at (-2, -6) and (2, 4). What is the slope-intercept equation for this line?
| y = -3x - 2 | |
| y = 2\(\frac{1}{2}\)x - 1 | |
| y = 2\(\frac{1}{2}\)x + 3 | |
| y = -3x + 2 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -6) and (2, 4) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(4.0) - (-6.0)}{(2) - (-2)} \) = \( \frac{10}{4} \)Plugging these values into the slope-intercept equation:
y = 2\(\frac{1}{2}\)x - 1
If AD = 27 and BD = 18, AB = ?
| 9 | |
| 11 | |
| 3 | |
| 2 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BD
The endpoints of this line segment are at (-2, 3) and (2, -5). What is the slope of this line?
| -2\(\frac{1}{2}\) | |
| 2 | |
| -2 | |
| 1 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 3) and (2, -5) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-5.0) - (3.0)}{(2) - (-2)} \) = \( \frac{-8}{4} \)The dimensions of this cylinder are height (h) = 2 and radius (r) = 4. What is the surface area?
| 48π | |
| 84π | |
| 16π | |
| 56π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(42) + 2π(4 x 2)
sa = 2π(16) + 2π(8)
sa = (2 x 16)π + (2 x 8)π
sa = 32π + 16π
sa = 48π
This diagram represents two parallel lines with a transversal. If b° = 164, what is the value of x°?
| 145 | |
| 164 | |
| 18 | |
| 169 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with b° = 164, the value of x° is 164.