ASVAB Math Knowledge Practice Test 566314 Results

Your Results Global Average
Questions 5 5
Correct 0 2.97
Score 0% 59%

Review

1

The dimensions of this trapezoid are a = 6, b = 6, c = 7, d = 2, and h = 4. What is the area?

50% Answer Correctly
24
16
18
12

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(6 + 2)(4)
a = ½(8)(4)
a = ½(32) = \( \frac{32}{2} \)
a = 16


2

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

all interior angles are right angles

the area is length x width

the lengths of all sides are equal

the perimeter is the sum of the lengths of all four sides


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


3

If the base of this triangle is 4 and the height is 7, what is the area?

58% Answer Correctly
14
49\(\frac{1}{2}\)
24
33

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 4 x 7 = \( \frac{28}{2} \) = 14


4

The formula for the area of a circle is which of the following?

77% Answer Correctly

a = π d

a = π d2

a = π r

a = π r2


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


5

Solve for y:
y2 + y - 2 = -y + 1

48% Answer Correctly
1 or -8
-1 or -5
8 or 2
1 or -3

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

y2 + y - 2 = -y + 1
y2 + y - 2 - 1 = -y
y2 + y + y - 3 = 0
y2 + 2y - 3 = 0

Next, factor the quadratic equation:

y2 + 2y - 3 = 0
(y - 1)(y + 3) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (y - 1) or (y + 3) must equal zero:

If (y - 1) = 0, y must equal 1
If (y + 3) = 0, y must equal -3

So the solution is that y = 1 or -3