| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.55 |
| Score | 0% | 71% |
What is 6a - 7a?
| 42a | |
| 13 | |
| -1a | |
| 42a2 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
6a - 7a = -1a
Simplify 4a x 8b.
| 32a2b2 | |
| 32\( \frac{a}{b} \) | |
| 32\( \frac{b}{a} \) | |
| 32ab |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
4a x 8b = (4 x 8) (a x b) = 32ab
This diagram represents two parallel lines with a transversal. If y° = 142, what is the value of c°?
| 38 | |
| 155 | |
| 16 | |
| 165 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with y° = 142, the value of c° is 38.
For this diagram, the Pythagorean theorem states that b2 = ?
c2 - a2 |
|
a2 - c2 |
|
c - a |
|
c2 + a2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
If the area of this square is 16, what is the length of one of the diagonals?
| 4\( \sqrt{2} \) | |
| 9\( \sqrt{2} \) | |
| 5\( \sqrt{2} \) | |
| \( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{16} \) = 4
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 42 + 42
c2 = 32
c = \( \sqrt{32} \) = \( \sqrt{16 x 2} \) = \( \sqrt{16} \) \( \sqrt{2} \)
c = 4\( \sqrt{2} \)