ASVAB Math Knowledge Practice Test 567795

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2c + 2c = 3c + 4z - 4 for c in terms of z.

3z + 3
-\(\frac{5}{9}\)z + \(\frac{5}{9}\)
-5\(\frac{1}{2}\)z - 3
-2z + 4