When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c + 3c = -9c - 8x + 3 for c in terms of x.
| -\(\frac{3}{5}\)x - 1\(\frac{3}{5}\) | |
| -4x + 5 | |
| -\(\frac{11}{12}\)x + \(\frac{1}{4}\) | |
| -5x - 5 |