| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.30 |
| Score | 0% | 46% |
On this circle, line segment CD is the:
diameter |
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circumference |
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radius |
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chord |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
obtuse, acute |
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supplementary, vertical |
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vertical, supplementary |
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acute, obtuse |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).
The formula for the area of a circle is which of the following?
c = π r |
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c = π r2 |
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c = π d |
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c = π d2 |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
Simplify (y + 8)(y + 7)
| y2 - 15y + 56 | |
| y2 - y - 56 | |
| y2 + y - 56 | |
| y2 + 15y + 56 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y + 8)(y + 7)
(y x y) + (y x 7) + (8 x y) + (8 x 7)
y2 + 7y + 8y + 56
y2 + 15y + 56
Solve -5b - 2b = -2b - 5z - 5 for b in terms of z.
| 11z + 6 | |
| 1\(\frac{1}{4}\)z + 1\(\frac{1}{4}\) | |
| z + 1\(\frac{2}{3}\) | |
| \(\frac{1}{3}\)z - 1\(\frac{1}{2}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
-5b - 2z = -2b - 5z - 5
-5b = -2b - 5z - 5 + 2z
-5b + 2b = -5z - 5 + 2z
-3b = -3z - 5
b = \( \frac{-3z - 5}{-3} \)
b = \( \frac{-3z}{-3} \) + \( \frac{-5}{-3} \)
b = z + 1\(\frac{2}{3}\)