ASVAB Math Knowledge Practice Test 570374 Results

Your Results Global Average
Questions 5 5
Correct 0 3.04
Score 0% 61%

Review

1

Simplify 6a x 3b.

85% Answer Correctly
18ab
9ab
18\( \frac{a}{b} \)
18\( \frac{b}{a} \)

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

6a x 3b = (6 x 3) (a x b) = 18ab


2

If the area of this square is 49, what is the length of one of the diagonals?

68% Answer Correctly
3\( \sqrt{2} \)
8\( \sqrt{2} \)
4\( \sqrt{2} \)
7\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)


3

A cylinder with a radius (r) and a height (h) has a surface area of:

53% Answer Correctly

π r2h

4π r2

2(π r2) + 2π rh

π r2h2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


4

The dimensions of this cylinder are height (h) = 1 and radius (r) = 6. What is the surface area?

48% Answer Correctly
36π
84π
80π
20π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(62) + 2π(6 x 1)
sa = 2π(36) + 2π(6)
sa = (2 x 36)π + (2 x 6)π
sa = 72π + 12π
sa = 84π


5

Solve for c:
c2 - 44 = -c - 2

48% Answer Correctly
6 or -7
6 or -9
2 or -1
4 or -5

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

c2 - 44 = -c - 2
c2 - 44 + 2 = -c
c2 + + c - 42 = 0
c2 + c - 42 = 0

Next, factor the quadratic equation:

c2 + c - 42 = 0
(c - 6)(c + 7) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 6) or (c + 7) must equal zero:

If (c - 6) = 0, c must equal 6
If (c + 7) = 0, c must equal -7

So the solution is that c = 6 or -7