| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.47 |
| Score | 0% | 49% |
Solve for z:
z2 - 10z + 16 = 0
| 2 or 8 | |
| 3 or 1 | |
| 2 or -5 | |
| 1 or 1 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
z2 - 10z + 16 = 0
(z - 2)(z - 8) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z - 2) or (z - 8) must equal zero:
If (z - 2) = 0, z must equal 2
If (z - 8) = 0, z must equal 8
So the solution is that z = 2 or 8
The dimensions of this cylinder are height (h) = 7 and radius (r) = 2. What is the surface area?
| 196π | |
| 154π | |
| 16π | |
| 36π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(22) + 2π(2 x 7)
sa = 2π(4) + 2π(14)
sa = (2 x 4)π + (2 x 14)π
sa = 8π + 28π
sa = 36π
Solve -8b - 3b = -6b - 3z + 6 for b in terms of z.
| -3z + 1 | |
| 2\(\frac{1}{4}\)z - 1\(\frac{1}{4}\) | |
| z - 3 | |
| -\(\frac{3}{8}\)z + \(\frac{1}{4}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
-8b - 3z = -6b - 3z + 6
-8b = -6b - 3z + 6 + 3z
-8b + 6b = -3z + 6 + 3z
-2b = + 6
b = \( \frac{ + 6}{-2} \)
b = \( \frac{}{-2} \) + \( \frac{6}{-2} \)
b = z - 3
If the base of this triangle is 8 and the height is 8, what is the area?
| 32 | |
| 32\(\frac{1}{2}\) | |
| 27\(\frac{1}{2}\) | |
| 63 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 8 x 8 = \( \frac{64}{2} \) = 32
Solve for a:
-9a - 3 = \( \frac{a}{8} \)
| -\(\frac{9}{10}\) | |
| -\(\frac{24}{73}\) | |
| 4 | |
| 2\(\frac{1}{4}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-9a - 3 = \( \frac{a}{8} \)
8 x (-9a - 3) = a
(8 x -9a) + (8 x -3) = a
-72a - 24 = a
-72a - 24 - a = 0
-72a - a = 24
-73a = 24
a = \( \frac{24}{-73} \)
a = -\(\frac{24}{73}\)