ASVAB Math Knowledge Practice Test 570487 Results

Your Results Global Average
Questions 5 5
Correct 0 2.47
Score 0% 49%

Review

1

Solve for z:
z2 - 10z + 16 = 0

59% Answer Correctly
2 or 8
3 or 1
2 or -5
1 or 1

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

z2 - 10z + 16 = 0
(z - 2)(z - 8) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (z - 2) or (z - 8) must equal zero:

If (z - 2) = 0, z must equal 2
If (z - 8) = 0, z must equal 8

So the solution is that z = 2 or 8


2

The dimensions of this cylinder are height (h) = 7 and radius (r) = 2. What is the surface area?

48% Answer Correctly
196π
154π
16π
36π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(22) + 2π(2 x 7)
sa = 2π(4) + 2π(14)
sa = (2 x 4)π + (2 x 14)π
sa = 8π + 28π
sa = 36π


3

Solve -8b - 3b = -6b - 3z + 6 for b in terms of z.

35% Answer Correctly
-3z + 1
2\(\frac{1}{4}\)z - 1\(\frac{1}{4}\)
z - 3
-\(\frac{3}{8}\)z + \(\frac{1}{4}\)

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

-8b - 3z = -6b - 3z + 6
-8b = -6b - 3z + 6 + 3z
-8b + 6b = -3z + 6 + 3z
-2b = + 6
b = \( \frac{ + 6}{-2} \)
b = \( \frac{}{-2} \) + \( \frac{6}{-2} \)
b = z - 3


4

If the base of this triangle is 8 and the height is 8, what is the area?

58% Answer Correctly
32
32\(\frac{1}{2}\)
27\(\frac{1}{2}\)
63

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 8 x 8 = \( \frac{64}{2} \) = 32


5

Solve for a:
-9a - 3 = \( \frac{a}{8} \)

46% Answer Correctly
-\(\frac{9}{10}\)
-\(\frac{24}{73}\)
4
2\(\frac{1}{4}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-9a - 3 = \( \frac{a}{8} \)
8 x (-9a - 3) = a
(8 x -9a) + (8 x -3) = a
-72a - 24 = a
-72a - 24 - a = 0
-72a - a = 24
-73a = 24
a = \( \frac{24}{-73} \)
a = -\(\frac{24}{73}\)