When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -c + 2c = 4c + 8y - 6 for c in terms of y.
| -1\(\frac{1}{5}\)y + 1\(\frac{1}{5}\) | |
| \(\frac{5}{14}\)y - \(\frac{9}{14}\) | |
| 3\(\frac{1}{2}\)y - 4\(\frac{1}{2}\) | |
| 2y + 1 |