| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.80 |
| Score | 0% | 56% |
Which of the following statements about math operations is incorrect?
you can add monomials that have the same variable and the same exponent |
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you can multiply monomials that have different variables and different exponents |
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you can subtract monomials that have the same variable and the same exponent |
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all of these statements are correct |
You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.
The dimensions of this cylinder are height (h) = 6 and radius (r) = 5. What is the surface area?
| 72π | |
| 110π | |
| 60π | |
| 224π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(52) + 2π(5 x 6)
sa = 2π(25) + 2π(30)
sa = (2 x 25)π + (2 x 30)π
sa = 50π + 60π
sa = 110π
If b = 8 and x = 4, what is the value of -6b(b - x)?
| 64 | |
| -24 | |
| -192 | |
| 70 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
-6b(b - x)
-6(8)(8 - 4)
-6(8)(4)
(-48)(4)
-192
Which of the following statements about a parallelogram is not true?
the area of a parallelogram is base x height |
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the perimeter of a parallelogram is the sum of the lengths of all sides |
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a parallelogram is a quadrilateral |
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opposite sides and adjacent angles are equal |
A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).
Find the value of b:
5b + z = -8
-5b - 5z = 8
| \(\frac{23}{45}\) | |
| \(\frac{26}{61}\) | |
| -1\(\frac{3}{5}\) |
You need to find the value of b so solve the first equation in terms of z:
5b + z = -8
z = -8 - 5b
then substitute the result (-8 - 5b) into the second equation:
-5b - 5(-8 - 5b) = 8
-5b + (-5 x -8) + (-5 x -5b) = 8
-5b + 40 + 25b = 8
-5b + 25b = 8 - 40
20b = -32
b = \( \frac{-32}{20} \)
b = -1\(\frac{3}{5}\)