| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.22 |
| Score | 0% | 64% |
The dimensions of this cylinder are height (h) = 7 and radius (r) = 1. What is the volume?
| 49π | |
| 72π | |
| 7π | |
| 175π |
The volume of a cylinder is πr2h:
v = πr2h
v = π(12 x 7)
v = 7π
If AD = 27 and BD = 17, AB = ?
| 2 | |
| 5 | |
| 3 | |
| 10 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDIf angle a = 51° and angle b = 63° what is the length of angle d?
| 153° | |
| 133° | |
| 129° | |
| 111° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 51° - 63° = 66°
So, d° = 63° + 66° = 129°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 51° = 129°
Solve for z:
z2 + 13z + 36 = 0
| -2 or -9 | |
| 1 or -2 | |
| -4 or -9 | |
| -6 or -7 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
z2 + 13z + 36 = 0
(z + 4)(z + 9) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z + 4) or (z + 9) must equal zero:
If (z + 4) = 0, z must equal -4
If (z + 9) = 0, z must equal -9
So the solution is that z = -4 or -9
If the area of this square is 1, what is the length of one of the diagonals?
| 2\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) | |
| \( \sqrt{2} \) | |
| 5\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{1} \) = 1
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 12 + 12
c2 = 2
c = \( \sqrt{2} \)