| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.46 |
| Score | 0% | 49% |
The formula for the area of a circle is which of the following?
c = π d2 |
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c = π r |
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c = π r2 |
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c = π d |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
The formula for the area of a circle is which of the following?
a = π r |
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a = π d |
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a = π r2 |
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a = π d2 |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
Which of the following statements about a triangle is not true?
perimeter = sum of side lengths |
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area = ½bh |
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exterior angle = sum of two adjacent interior angles |
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sum of interior angles = 180° |
A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.
Solve for z:
-2z + 7 < 2 + 4z
| z < \(\frac{5}{6}\) | |
| z < -6 | |
| z < -3 | |
| z < \(\frac{1}{9}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-2z + 7 < 2 + 4z
-2z < 2 + 4z - 7
-2z - 4z < 2 - 7
-6z < -5
z < \( \frac{-5}{-6} \)
z < \(\frac{5}{6}\)
Solve -2a - 6a = -6a + 5y + 8 for a in terms of y.
| -y - 2 | |
| \(\frac{1}{4}\)y + \(\frac{5}{12}\) | |
| \(\frac{4}{5}\)y - \(\frac{1}{2}\) | |
| 2\(\frac{3}{4}\)y + 2 |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
-2a - 6y = -6a + 5y + 8
-2a = -6a + 5y + 8 + 6y
-2a + 6a = 5y + 8 + 6y
4a = 11y + 8
a = \( \frac{11y + 8}{4} \)
a = \( \frac{11y}{4} \) + \( \frac{8}{4} \)
a = 2\(\frac{3}{4}\)y + 2