| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.28 |
| Score | 0% | 66% |
If a = 8, b = 4, c = 2, and d = 3, what is the perimeter of this quadrilateral?
| 22 | |
| 16 | |
| 17 | |
| 26 |
Perimeter is equal to the sum of the four sides:
p = a + b + c + d
p = 8 + 4 + 2 + 3
p = 17
If side a = 5, side b = 5, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{13} \) | |
| \( \sqrt{82} \) | |
| \( \sqrt{50} \) | |
| \( \sqrt{41} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 52 + 52
c2 = 25 + 25
c2 = 50
c = \( \sqrt{50} \)
Solve for y:
6y - 4 > 4 - 9y
| y > \(\frac{1}{6}\) | |
| y > -1 | |
| y > -4\(\frac{1}{2}\) | |
| y > \(\frac{8}{15}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
6y - 4 > 4 - 9y
6y > 4 - 9y + 4
6y + 9y > 4 + 4
15y > 8
y > \( \frac{8}{15} \)
y > \(\frac{8}{15}\)
Find the value of a:
-3a + z = -2
-6a + 6z = 5
| \(\frac{7}{16}\) | |
| 1\(\frac{5}{12}\) | |
| 1\(\frac{8}{17}\) | |
You need to find the value of a so solve the first equation in terms of z:
-3a + z = -2
z = -2 + 3a
then substitute the result (-2 - -3a) into the second equation:
-6a + 6(-2 + 3a) = 5
-6a + (6 x -2) + (6 x 3a) = 5
-6a - 12 + 18a = 5
-6a + 18a = 5 + 12
12a = 17
a = \( \frac{17}{12} \)
a = 1\(\frac{5}{12}\)
The formula for the area of a circle is which of the following?
a = π d |
|
a = π d2 |
|
a = π r |
|
a = π r2 |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.