| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.70 |
| Score | 0% | 54% |
Which of the following statements about a triangle is not true?
perimeter = sum of side lengths |
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exterior angle = sum of two adjacent interior angles |
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sum of interior angles = 180° |
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area = ½bh |
A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.
Solve for c:
-c - 1 = \( \frac{c}{5} \)
| \(\frac{4}{5}\) | |
| -2\(\frac{4}{7}\) | |
| -\(\frac{5}{6}\) | |
| -\(\frac{3}{5}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-c - 1 = \( \frac{c}{5} \)
5 x (-c - 1) = c
(5 x -c) + (5 x -1) = c
-5c - 5 = c
-5c - 5 - c = 0
-5c - c = 5
-6c = 5
c = \( \frac{5}{-6} \)
c = -\(\frac{5}{6}\)
For this diagram, the Pythagorean theorem states that b2 = ?
c2 + a2 |
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c2 - a2 |
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c - a |
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a2 - c2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
The formula for the area of a circle is which of the following?
a = π r |
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a = π d2 |
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a = π d |
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a = π r2 |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
Solve for c:
-7c - 8 > \( \frac{c}{-7} \)
| c > 4 | |
| c > 3\(\frac{1}{3}\) | |
| c > -1\(\frac{1}{6}\) | |
| c > -5\(\frac{2}{5}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
-7c - 8 > \( \frac{c}{-7} \)
-7 x (-7c - 8) > c
(-7 x -7c) + (-7 x -8) > c
49c + 56 > c
49c + 56 - c > 0
49c - c > -56
48c > -56
c > \( \frac{-56}{48} \)
c > -1\(\frac{1}{6}\)