ASVAB Math Knowledge Practice Test 576857

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -3b - 2b = 4b - 3z - 6 for b in terms of z.

6z - 2
-\(\frac{5}{12}\)z + \(\frac{1}{12}\)
-13z - 4
\(\frac{1}{7}\)z + \(\frac{6}{7}\)