When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -2b + 5b = b + 5z - 1 for b in terms of z.
| z - 2\(\frac{2}{3}\) | |
| \(\frac{5}{12}\)z - \(\frac{7}{12}\) | |
| \(\frac{1}{2}\)z + 1 | |
| z + \(\frac{1}{3}\) |