ASVAB Math Knowledge Practice Test 579761 Results

Your Results Global Average
Questions 5 5
Correct 0 2.76
Score 0% 55%

Review

1

Solve for x:
x2 - 64 = 0

58% Answer Correctly
-1 or -6
7 or -4
8 or -6
8 or -8

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

x2 - 64 = 0
(x - 8)(x + 8) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (x - 8) or (x + 8) must equal zero:

If (x - 8) = 0, x must equal 8
If (x + 8) = 0, x must equal -8

So the solution is that x = 8 or -8


2

The dimensions of this cube are height (h) = 8, length (l) = 3, and width (w) = 3. What is the surface area?

51% Answer Correctly
58
184
114
322

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 3 x 3) + (2 x 3 x 8) + (2 x 3 x 8)
sa = (18) + (48) + (48)
sa = 114


3

Simplify (6a)(8ab) + (4a2)(8b).

65% Answer Correctly
168ab2
80a2b
16ab2
80ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(8ab) + (4a2)(8b)
(6 x 8)(a x a x b) + (4 x 8)(a2 x b)
(48)(a1+1 x b) + (32)(a2b)
48a2b + 32a2b
80a2b


4

If angle a = 34° and angle b = 64° what is the length of angle d?

56% Answer Correctly
146°
144°
130°
155°

Solution

An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:

d° = b° + c°

To find angle c, remember that the sum of the interior angles of a triangle is 180°:

180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 34° - 64° = 82°

So, d° = 64° + 82° = 146°

A shortcut to get this answer is to remember that angles around a line add up to 180°:

a° + d° = 180°
d° = 180° - a°
d° = 180° - 34° = 146°


5

Solve for b:
-7b + 1 = \( \frac{b}{-5} \)

46% Answer Correctly
-\(\frac{20}{23}\)
\(\frac{6}{7}\)
\(\frac{5}{34}\)
1\(\frac{2}{3}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-7b + 1 = \( \frac{b}{-5} \)
-5 x (-7b + 1) = b
(-5 x -7b) + (-5 x 1) = b
35b - 5 = b
35b - 5 - b = 0
35b - b = 5
34b = 5
b = \( \frac{5}{34} \)
b = \(\frac{5}{34}\)