| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.01 |
| Score | 0% | 40% |
Solve for b:
7b - 5 > \( \frac{b}{-5} \)
| b > 1\(\frac{1}{20}\) | |
| b > \(\frac{6}{19}\) | |
| b > \(\frac{25}{36}\) | |
| b > \(\frac{12}{35}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
7b - 5 > \( \frac{b}{-5} \)
-5 x (7b - 5) > b
(-5 x 7b) + (-5 x -5) > b
-35b + 25 > b
-35b + 25 - b > 0
-35b - b > -25
-36b > -25
b > \( \frac{-25}{-36} \)
b > \(\frac{25}{36}\)
If the length of AB equals the length of BD, point B __________ this line segment.
intersects |
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trisects |
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midpoints |
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bisects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.
The endpoints of this line segment are at (-2, 10) and (2, -2). What is the slope-intercept equation for this line?
| y = -3x + 4 | |
| y = -x + 0 | |
| y = -3x - 4 | |
| y = x - 4 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 4. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 10) and (2, -2) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-2.0) - (10.0)}{(2) - (-2)} \) = \( \frac{-12}{4} \)Plugging these values into the slope-intercept equation:
y = -3x + 4
The formula for the area of a circle is which of the following?
c = π d2 |
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c = π r2 |
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c = π d |
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c = π r |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
Solve for x:
x2 + x - 30 = x - 5
| 6 or -4 | |
| 5 or -5 | |
| -4 or -5 | |
| 6 or -3 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
x2 + x - 30 = x - 5
x2 + x - 30 + 5 = x
x2 + x - x - 25 = 0
x2 - 25 = 0
Next, factor the quadratic equation:
x2 - 25 = 0
(x - 5)(x + 5) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (x - 5) or (x + 5) must equal zero:
If (x - 5) = 0, x must equal 5
If (x + 5) = 0, x must equal -5
So the solution is that x = 5 or -5