ASVAB Math Knowledge Practice Test 580806 Results

Your Results Global Average
Questions 5 5
Correct 0 2.92
Score 0% 58%

Review

1

Solve 7b - 7b = -2b + 4y - 9 for b in terms of y.

34% Answer Correctly
1\(\frac{2}{9}\)y - 1
-\(\frac{1}{4}\)y - \(\frac{3}{4}\)
16y - 4
\(\frac{7}{8}\)y + \(\frac{1}{4}\)

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

7b - 7y = -2b + 4y - 9
7b = -2b + 4y - 9 + 7y
7b + 2b = 4y - 9 + 7y
9b = 11y - 9
b = \( \frac{11y - 9}{9} \)
b = \( \frac{11y}{9} \) + \( \frac{-9}{9} \)
b = 1\(\frac{2}{9}\)y - 1


2

If side x = 12cm, side y = 5cm, and side z = 10cm what is the perimeter of this triangle?

84% Answer Correctly
30cm
39cm
27cm
29cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 12cm + 5cm + 10cm = 27cm


3

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

c2 - a2

a2 - c2

c2 + a2

c - a


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)


4

A(n) __________ is two expressions separated by an equal sign.

76% Answer Correctly

equation

formula

problem

expression


Solution

An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.


5

The dimensions of this trapezoid are a = 6, b = 3, c = 8, d = 2, and h = 5. What is the area?

50% Answer Correctly
18
22\(\frac{1}{2}\)
12\(\frac{1}{2}\)
13\(\frac{1}{2}\)

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(3 + 2)(5)
a = ½(5)(5)
a = ½(25) = \( \frac{25}{2} \)
a = 12\(\frac{1}{2}\)