| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.56 |
| Score | 0% | 51% |
Simplify (6a)(2ab) - (5a2)(4b).
| -8a2b | |
| 72a2b | |
| 32ab2 | |
| 72ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(6a)(2ab) - (5a2)(4b)
(6 x 2)(a x a x b) - (5 x 4)(a2 x b)
(12)(a1+1 x b) - (20)(a2b)
12a2b - 20a2b
-8a2b
On this circle, line segment CD is the:
diameter |
|
circumference |
|
chord |
|
radius |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
For this diagram, the Pythagorean theorem states that b2 = ?
c - a |
|
c2 + a2 |
|
c2 - a2 |
|
a2 - c2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
Factor y2 - 9
| (y + 3)(y + 3) | |
| (y - 3)(y - 3) | |
| (y + 3)(y - 3) | |
| (y - 3)(y + 3) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -9 as well and sum (Inside, Outside) to equal 0. For this problem, those two numbers are -3 and 3. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 - 9
y2 + (-3 + 3)y + (-3 x 3)
(y - 3)(y + 3)
The dimensions of this cylinder are height (h) = 3 and radius (r) = 3. What is the surface area?
| 198π | |
| 54π | |
| 36π | |
| 8π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(32) + 2π(3 x 3)
sa = 2π(9) + 2π(9)
sa = (2 x 9)π + (2 x 9)π
sa = 18π + 18π
sa = 36π