ASVAB Math Knowledge Practice Test 581616 Results

Your Results Global Average
Questions 5 5
Correct 0 2.56
Score 0% 51%

Review

1

Simplify (6a)(2ab) - (5a2)(4b).

62% Answer Correctly
-8a2b
72a2b
32ab2
72ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(2ab) - (5a2)(4b)
(6 x 2)(a x a x b) - (5 x 4)(a2 x b)
(12)(a1+1 x b) - (20)(a2b)
12a2b - 20a2b
-8a2b


2

On this circle, line segment CD is the:

46% Answer Correctly

diameter

circumference

chord

radius


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


3

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

c - a

c2 + a2

c2 - a2

a2 - c2


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)


4

Factor y2 - 9

54% Answer Correctly
(y + 3)(y + 3)
(y - 3)(y - 3)
(y + 3)(y - 3)
(y - 3)(y + 3)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -9 as well and sum (Inside, Outside) to equal 0. For this problem, those two numbers are -3 and 3. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 - 9
y2 + (-3 + 3)y + (-3 x 3)
(y - 3)(y + 3)


5

The dimensions of this cylinder are height (h) = 3 and radius (r) = 3. What is the surface area?

48% Answer Correctly
198π
54π
36π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(32) + 2π(3 x 3)
sa = 2π(9) + 2π(9)
sa = (2 x 9)π + (2 x 9)π
sa = 18π + 18π
sa = 36π