ASVAB Math Knowledge Practice Test 581728

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2c - 6c = 8c + 7z - 6 for c in terms of z.

-\(\frac{1}{3}\)z - 1
\(\frac{6}{7}\)z + 1\(\frac{1}{7}\)
-2\(\frac{1}{6}\)z + 1
-\(\frac{3}{13}\)z - \(\frac{1}{13}\)